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the volume of the gas. Another method which answers the same purpose is due to Langevin (_Ann. Chim. Phys._, 1903, 28, p. 289); it is as follows. Let A and B be two parallel planes immersed in a gas, and let a slab of the gas bounded by the planes a, b parallel to A and B be ionized by an instantaneous flash of Rontgen rays. If A and B are at different electric potentials, then all the positive ions produced by the rays will be attracted by the negative plate and all the negative ions by the positive, if the electric field were exceedingly large they would reach these plates before they had time to recombine, so that each plate would receive N0 ions if the flash of Rontgen rays produced N0 positive and N0 negative ions. With weaker fields the number of ions received by the plates will be less as some of them will recombine before they can reach the plates. We can find the number of ions which reach the plates in this case in the following way:--In consequence of the movement of the ions the slab of ionized gas will broaden out and will consist of three portions, one in which there are nothing but positive ions,--this is on the side of the negative plate,--another on the side of the positive plate in which there are nothing but negative ions, and a portion between these in which there are both positive and negative ions; it is in this layer that recombination takes place, and here if n is the number of positive or negative ions at the time t after the flash of Rontgen rays, n = n0/(1 + [alpha]n0t). With the same notation as before, the breadth of either of the outer layers will in time dt increase by X(k1 + k2)dt, and the number of ions in it by X(k1 + k2)ndt; these ions will reach the plate, the outer layers will receive fresh ions until the middle one disappears, which it will do after a time l/X(k1 + k2), where l is the thickness of the slab ab of ionized gas; hence N, the number of ions reaching either plate, is given by the equation _ / l/X(k1+k2) n0X(k1 + k2) X(k1 + k2) / n0[alpha]l \ N = | --------------dt = ---------- log( 1 + ---------- ). _/ 0 1 + n0[alpha]t [alpha] \ X(k1 + k2) / If Q is the charge received by the plate, X / Q0[epsilon]\ Q = Ne = -------------- log ( 1 + ----------- ), 4[pi][epsilon] \
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