FREE BOOKS

Author's List




PREV.   NEXT  
|<   114   115   116   117   118   119   120   121   122   123   124   125   126   127   128   129   130   131   132   133   134   135   136   137   138  
139   140   141   142   143   144   145   146   147   148   149   150   151   152   153   154   155   156   157   158   159   160   161   162   163   >>   >|  
to Euler. The reader will find the theory completely treated in Chrystal's _Algebra_, where will be found the exhibition of a prime number of the form 4p + 1 as the actual sum of two squares by means of continuants, a result given by H. J. S. Smith. The continuant / b2, b3, ..., b_{n}\ K ( ) is also equal to the determinant \a1, a2, a3, ..., a_{n}/ is also equal to the determinant | a1 b2 0 0 . . . 0 | | -1 a2 b3 0 . . . 0 | | 0 -1 a3 b4 . . . 0 | | 0 0 -1 a4 b5 . . -- | | | | u -1 a_{n-1} b_{n} | | 0 0 -- -- 0 0 -1 a_{n} |, from which point of view continuants have been treated by W. Spottiswoode, J. J. Sylvester and T. Muir. Most of the theorems concerning continued fractions can be thus proved simply from the properties of determinants (see T. Muir's _Theory of Determinants_, chap. iii.). Perhaps the earliest appearance in analysis of a continuant in its determinant form occurs in Lagrange's investigation of the vibrations of a stretched string (see Lord Rayleigh, _Theory of Sound_, vol. i. chap. iv.). _The Conversion of Series and Products into Continued Fractions._ 1. A continued fraction may always be found whose n^{th} convergent shall be equal to the sum to n terms of a given series or the product to n factors of a given continued product. In fact, a continued fraction b1 b2 b_{n} -- -- ----- can be constructed having for the a1 + a2 + ... + a_{n} + ... numerators of its successive convergents any assigned quantities p1, p2, p3, ..., p_{n}, and for their denominators any assigned quantities q1, q2, q3, ..., q_{n} ... The partial fraction b_{n}/a_{n} corresponding to the n^{th} convergent can be found from the relations p_n = a_{n}p_{n-1} + b_{n}p_{n-2}, q_n = a_{n}q_{n-1} + b_{n}q_{n-2}; and the first two partial quotients are given by b1 = p1, a1 = q1, b1a2 = p2, a1a2 + b2 = q2. If we form then the continued fraction in which p1, p2, p3, ..., p_{n} are u1, u1 + u2, u1 + u2 + u3, ..., u1 + u2 + ..., u_{n}, and q1, q2, q3, ..., q_{n} are all unity, we find the series u1 + u2 + ..., u_{n} equivalent to the continued fraction u1 u2/u1 u3/u2 u_n/u_{n-1} -- ------ ------ ---------- 1 - u2
PREV.   NEXT  
|<   114   115   116   117   118   119   120   121   122   123   124   125   126   127   128   129   130   131   132   133   134   135   136   137   138  
139   140   141   142   143   144   145   146   147   148   149   150   151   152   153   154   155   156   157   158   159   160   161   162   163   >>   >|  



Top keywords:
continued
 

fraction

 

determinant

 
series
 

product

 

convergent

 

Theory

 

quantities

 

assigned

 

continuant


treated

 
partial
 

continuants

 
quotients
 
Continued
 

Products

 

Fractions

 

equivalent

 

successive

 

numerators


convergents

 

relations

 

Series

 

constructed

 

denominators

 
factors
 

determinants

 

result

 

squares

 

Chrystal


Algebra

 

completely

 
theory
 

reader

 

exhibition

 

actual

 

number

 

Spottiswoode

 

Sylvester

 

vibrations


stretched
 
investigation
 

Lagrange

 

analysis

 

occurs

 
string
 

Rayleigh

 
appearance
 
earliest
 

fractions