the polygon of external forces, and 69 c is half the
reciprocal figure. The complete reciprocal figure is shown in fig. 69 a.

The method of sections already described is often more convenient than the
method of reciprocal figures, and the method of influence lines is also
often the readiest way of dealing with braced girders.

35. _Chain Loaded uniformly along a Horizontal Line._--If the lengths of
the links be assumed indefinitely short, the chain under given simple
distributions of load will take the form of comparatively simple
mathematical curves known as catenaries. The true catenary is that assumed
by a chain of uniform weight per unit of length, but the form generally
adopted for suspension bridges is that assumed by a chain under a weight
uniformly distributed relatively to a horizontal line. This curve is a
parabola.

Remembering that in this case the centre bending moment [Sigma]wl will be
equal to wL squared/8, we see that the horizontal tension H at the vertex for a
span L (the points of support being at equal heights) is given by the
expression

1 . . . H = wL squared/8y,

or, calling x the distance from the vertex to the point of support,

H = wx squared/2y,

The value of H is equal to the maximum tension on the bottom flange, or
compression on the top flange, of a girder of equal span, equally and
similarly loaded, and having a depth equal to the dip of the suspension
bridge.

[Illustration: FIG. 70.]

Consider any other point F of the curve, fig. 70, at a distance x [v.04
p.0556] from the vertex, the horizontal component of the resultant (tangent
to the curve) will be unaltered; the vertical component V will be simply
the sum of the loads between O and F, or wx. In the triangle FDC, let FD be
tangent to the curve, FC vertical, and DC horizontal; these three sides
will necessarily be proportional respectively to the resultant tension
along the chain at F, the vertical force V passing through the point D, and
the horizontal tension at O; hence

H : V = DC : FC = wx squared/2y : wx = x/2 : y,

hence DC is the half of OC, proving the curve to be a parabola.

The value of R, the tension at any point at a distance x from the vertex,
is obtained from the equation

R squared = H squared+V squared = w squaredx^4/4y squared+w squaredx squared,

or,

2 . . . R = wx[root](1+x squared/4y squared).

Let i be the angle between the tangent at any point having the co-ordinates
x and y measu