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at F. If this process is repeated for all positions of the load, we get the influence line AGB for the bending moment at C. The area AGB is termed the influence area. The greatest moment CG at C is x(l-x)/l. To use this line to investigate the maximum moment at C due to a series of travelling loads at fixed distances, let P_1, P_2, P_3, ... be the loads which at the moment considered are at distances m_1, m_2, ... from the left abutment. Set off these distances along AB and let y_1, y_2, ... be the corresponding ordinates of the influence curve (y = Ff) on the verticals under the loads. Then the moment at C due to all the loads is M = P_1y_1+P_2y_2+... [v.04 p.0553] [Illustration: FIG. 53.] The position of the loads which gives the greatest moment at C may be settled by the criterion given above. For a uniform travelling load w per ft. of span, consider a small interval Fk = [Delta]m on which the load is w[Delta]m. The moment due to this, at C, is wm(l-x)[Delta]m/l. But m(l-x)[Delta]m/l is the area of the strip Ffhk, that is y[Delta]m. Hence the moment of the load on [Delta]m at C is wy[Delta]m, and the moment of a uniform load over any portion of the girder is w x the area of the influence curve under that portion. If the scales are so chosen that a inch represents 1 in. ton of moment, and b inch represents 1 ft. of span, and w is in tons per ft. run, then ab is the unit of area in measuring the influence curve. If the load is carried by a rail girder (stringer) with cross girders at the intersections of bracing and boom, its effect is distributed to the bracing intersections D'E' (fig. 53), and the part of the influence line for that bay (panel) is altered. With unit load in the position shown, the load at D' is (p-n)/p, and that at E' is n/p. The moment of the load at C is m(l-x)/l-n(p-n)/p. This is the equation to the dotted line RS (fig. 52). [Illustration: FIG. 54.] [Illustration: FIG. 55] If the unit load is at F', the reaction at B' and the shear at C' is m/l, positive if the shearing stress resists a tendency of the part of the girder on the right to move upwards; set up Ff = m/l (fig. 54) on the vertical under the load. Repeating the process for other positions, we get the influence line AGHB, for the shear at C due to unit load anywhere on the girder. GC = x/l and CH = -(l-x)/l. The lines AG, HB are parallel. If the load is in the bay D'E' and is carried by a rail girder which distributes it
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