hiefly made.

Attached to the day column in Plate 29_c_ and running into 30_c_ is a
series which presents a difficulty I am unable to explain. The days and
numerals in this case are as follows:

III
Ix
Cauac } 16, VI; 16, IX; 16, XII; 16, (?)
Kan }
Muluc

The red numeral over the day column is very distinctly III in
Kingsborough's work, but is II, though somewhat blurred, in Foerstemann's
photograph. As III + 16 - 13 = VI, and the remaining numerals agree with
this result, III must be correct. Adding together the pairs and casting
out the thirteens, thus, III + 16 - 13 = VI; VI + 16 - 13 = IX; IX + 16 -
13 = XII; XII + 16 - 13 - 13 = II, we find the last red number, which is
wanting in both copies of the codex, to be II, whereas, according to the
theory advanced, it should be III. The sum of the black numerals (four
16's) is 64, while the interval between the days is 65. The only way of
correcting the mistake, if one has been made, is by arbitrarily changing
the last 16 to 17; but uniformity in the black numerals apparently
forbids this change and and[TN-3] indicates that the variation from the
usual rule must be accounted for in some other way.

In reference to this series, Dr. Foerstemann[292-1] remarks:

The column of the days has the difference 5; the fifth sign (in this
case really superfluous), that of the thirteenth day, appears in a
remarkable form, apparently as an inscription on a vessel. The black
figures ought to give the sum 65, but we get only 4 x 16, or 64. But
this appears to be merely an oversight by the copyist, for although
in the Codex Troano, also, we find 64 several times instead of 65,
still this has always appeared to me merely as a sign of the great
negligence of the copyist of that manuscript.

Turning to the Manuscript Troano, Plate XXVIII*_b_, we find a column
consisting of the four terminal days of the year, Been, Ezanab, Akbal,
and Lamat, which of course have the same relation to one another as the
first days. It is evident from the space that only four were intended to
be given. The numerals in Brasseur's fac simile are XI; 20, 12, IV; 9,
XIII; 10, X; 13, XI.

The red numeral over the column is XI, as is also the last of the series,
but the sum of the black numbers is only 64, which would give X as the
final number, as is evident from the following operation: XI + 32 - 13 -
13 - 13 = IV; IV + 9 = XIII; XIII + 10 - 13 = X; X + 1