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nous. The qualification "If the arc of swing is small" is introduced because, as was discovered by Christiaan Huygens, the arc of vibration of a truly isochronous pendulum should not be a circle with centre O, but a cycloid DM, generated by the rolling of a circle with diameter DQ = 1/2OD, upon a straight line QM. However, for a short distance near the bottom, the circle so nearly coincides with the cycloid that a pendulum swinging in the usual circular path is, for small arcs, isochronous for practical purposes. [Illustration: FIG. 6.] The formula representing the time of oscillation of a pendulum, in a circular arc, is thus found:--Let OB (fig. 6) be the pendulum, B be the position from which the bob is let go, and P be its position at some period during its swing. Put FC = h, and MC = x, and OB = l. Now when a body is allowed to move under the force of gravity in any path from a height h, the velocity it attains is the same as a body would attain falling freely vertically through the distance h. Whence if v be the velocity of the bob at P, v = sqrt(2gFM) = sqrt(2g(h - x)). Let Pp = ds, and the vertical distance of p below P = dx, then Pp = velocity at P X dt; that is, dt = ds/v. ds l l Also -- = -- = ---------------, dx MP sqrt(x(2l - x)) ds ldx 1 whence dt = -- = --------------- . --------------- v sqrt(x(2l - x)) sqrt(2g(h - x)) 1 / l dx 1 = --- / --- . -------------- . ---------------- 2 \/ g sqrt(x(p - x)) sqrt(1 - (x/2l)) Expanding the second part we have 1 / l dx / x \ dt = --- / --- . -------------- . ( 1 + --- + ... ). 2 \/ g sqrt(x(h - x)) \ 4l / If this is integrated between the limits of 0 and h, we have / l / h \ t = [pi] / --- . ( 1 + --- + ... ), \/ g \ 8l / where t is the time of swing from B to A. The terms after the second may be neglected. The first term, [pi] sqrt(l/g), is the time of swing in a cycloid. The second part represents the addition necessary if the swing is circular and not cycloidal, and therefore expresses the "circular error." Now h = BC^2/l = 2[pi]^2[theta]^2l / 360^2, where [theta] is half the angle
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