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ith the perpendicular, the beam is reflected in such a way that its new path also makes an angle of 30 deg. with the perpendicular. If the sunbeam strikes the mirror at an angle of 32 deg. with the perpendicular, the path of the reflected ray also makes an angle of 32 deg. with the perpendicular. The ray (_AC_, Fig. 60) which falls upon the mirror is called the incident ray, and the angle which the incident ray (_AC_) makes with the perpendicular (_BC_) to the mirror, at the point where the ray strikes the mirror, is called the angle of incidence. The angle formed by the reflected ray (_CD_) and this same perpendicular is called the angle of reflection. Observation and experiment have taught us that light is always reflected in such a way that the angle of reflection equals the angle of incidence. Light is not the only illustration we have of the law of reflection. Every child who bounces a ball makes use of this law, but he uses it unconsciously. If an elastic ball is thrown perpendicularly against the floor, it returns to the sender; if it is thrown against the floor at an angle (Fig. 61), it rebounds in the opposite direction, but always in such a way that the angle of reflection equals the angle of incidence. [Illustration: FIG. 60.--The ray _AC_ is reflected as _CD_.] [Illustration: FIG. 61.--A bouncing ball illustrates the law of reflection.] 105. Why the Image seems to be behind the Mirror. If a candle is placed in front of a mirror, as in Figure 62, one of the rays of light which leaves the candle will fall upon the mirror as _AB_ and will be reflected as _BC_ (in such a way that the angle of reflection equals the angle of incidence). If an observer stands at _C_, he will think that the point _A_ of the candle is somewhere along the line _CB_ extended. Such a supposition would be justified from Section 102. But the candle sends out light in all directions; one ray therefore will strike the mirror as _AD_ and will be reflected as _DE_, and an observer at _E_ will think that the point _A_ of the candle is somewhere along the line _ED_. In order that both observers may be correct, that is, in order that the light may seem to be in both these directions, the image of the point _A_ must seem to be at the intersection of the two lines. In a similar manner it can be shown that every point of the image of the candle seems to be behind the mirror. [Illustration: FIG. 62.--The image is a duplicate of the object,
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